JavaScript Debugging

JavaScript Debugging

  

Hi, i try to follow this instruction to debug javascript:

https://success.outsystems.com/Documentation/10/Extensibility_and_Integration/JavaScript/Extend_Your_Web_Application_Using_JavaScript/Define_and_Run_JavaScript_Code

Unfortunately, i cannot write a javascript code that throw an error.

My javascript in a button click:

SyntaxEditor Code Snippet

function tryMe(msg){
    alert("in tryMe");
    throw 600;
    return true;
}

and my debug handler is:

SyntaxEditor Code Snippet

function IBJSDebug(event, excp, error_code, origin){
    alert("ERROR CODE #" + error_code + "\n" + origin + 
    "Exception.\nName:" + excp.name +
    "\nMessage:" + excp.message);
}

osRegisterExceptionHandler(IBJSDebug);

When i click the button, the handler is not executed.

How to make a javascript code that is error so that can be caught by the handler? thank you.

regards,

O

Is there someone who try the handler? Tq