How can I create a list without a source record?

Rank: #31074

How can I create a list without a source record?

Question

Application Type

Traditional Web

I'm trying to create a list of 8 items, with a different link for each item. It doesn't seem like I can do this by putting in the record source, so I created 8 individual items where I set the unique URLs. However, the list itself requires a source, and when I put in the source, it shows my 8 items repeated many times. Is there a way to make the list with dynamic URLs, or can I just make a list without a source somehow?

3 days ago

Agno Silveira

Rank: #173

Hi Joseph,

Can you share some images with an example of what you need, and your .OML for us to better understand what you need?

Greetings.

3 days ago

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Joseph Kuhn

Rank: #31074

OML is attached. Basically I have 8 different URLs, and I want to assign one URL to each of the items in my list. If I set the source of the list to the record, it populates it correctly, but I don't see a way for me to set each link separately (I can only set one for all of them). So I made 8 different items with different links, but now there are more than 8 items because of the source field. It is the popover item in the widget tree, under "Quote of the Year".

AwardsVoting.oml

3 days ago

Agno Silveira

Rank: #173

Replying to Joseph Kuhn's comment on 14 Jan 2021 21:24:32

okay,

a possible solution to solve your problem is to create a screen to register the "Quote of the Year",

see the CreateOrUpdateQuotesoftheYear screen.

I did this and registered 2 examples.

Then see the ListQuotesoftheYear screen, to understand how to list several registered links dynamically.

You can use this example to put it on the screen you need

OML is attached.