Hi. I'm using the Javascript API feedback method, as explained in documentation:
$public.FeedbackMessage.showFeedbackMessage("Your data has been submitted.", 1, true, "", false);
$public.FeedbackMessage.showFeedbackMessage(
"Your data has been submitted."
, 1,
true
,
""
false
);
Instead of the message, I can show an input parameter, this way:
$public.FeedbackMessage.showFeedbackMessage($parameters.MyParam, 1, true, "", false);
$public.FeedbackMessage.showFeedbackMessage($parameters.MyParam
I'd like to know how can I show a local variable which is declared in the module. I've tried somthing like this:
$public.FeedbackMessage.showFeedbackMessage($variables.MyVar, 1, true, "", false);
$public.FeedbackMessage.showFeedbackMessage($variables.MyVar
Well, you guess, it didn't work. Is it able to reach a local variable form javascript to be displayed in such a message?
Thanks.
Hello,Try to check this documentation (https://success.outsystems.com/Documentation/11/Extensibility_and_Integration/JavaScript/Extend_Your_Mobile_and_Reactive_Apps_Using_JavaScript#Use_input_and_output_parameters). It shows how to add input (and output) parameters to your javascript.Best regards,