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How to get a particular row of record from a list using filter?
Question
Application Type
Reactive

How to get a particular row of record from a list using filter for reactive? 

1. On screen 1 I am selecting a text and when I double click I expect that all the details should be displayed on screen 2. 

2. I am unable to get a particular row of record to display on screen 2. 

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Accelance Partners

Hi @Siddhi 

On the 1st screen, are you showing records in the table format? which you want to select and show that record's details on another screen? I am a bit confused about your functionality
Can you share your oml here?

Thanks,

Shriyash

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Siddhi Amilkanthwar

Yes, I am showing records in the table format on screen 1. Then I want to show the record details on another screen. 

This is my screen 1 and when I click on the label printing it should navigate to screen 2 and the details of this app name should display. 

Thank you. 

Screen 1.png
2026-03-12 06-20-48
KUNDAN CHAUHAN
Champion

Hi Siddhi Amilkanthwar ,

I'm attaching a demo screen please check it , 

Demo screen :https://personal-x1ixzlcz.outsystemscloud.com/Crud/Student

please tell us requirement  is like this..

Thanks 

UserImage.jpg
Siddhi Amilkanthwar

No actually. Suppose, when we click on random it should navigate me to the details page of random which is stored in backend and not the edit page for it. 

Thank you. 

2025-09-25 14-38-22
Lokesh Kumar Yadav

Hi Siddhi 

I'm attaching a demo screen please check it , 

Demo Screen: Movies (personal-udaksfpd.outsystemscloud.com) 




image1.PNG
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Siddhi Amilkanthwar

Yes, this is what I want. But including the info displayed I need more information of the same which is saved in the backend. 

2025-09-25 14-38-22
Lokesh Kumar Yadav

Hi Siddhi,

You have to go to detail section and go to properties and put enable value to the false 

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Siddhi Amilkanthwar

Hello Lokesh, 

I am very new to OutSystem, so could you help me with a sample oml file? 


2025-09-25 14-38-22
Lokesh Kumar Yadav

Hi Siddhi,

I attached the oml file and in your senario you have to do enable the false

MovieDetail.oml
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Siddhi Amilkanthwar

Hello @Lokesh Yadav

I am unable to see the output.  I have attached the screenshot. 

Screenshot 2022-09-30 at 11.28.14 AM.png
2026-02-26 06-29-24
Rahul
 
MVP

Hi @Siddhi Amilkanthwar ,

why you are doing list filter , 

1.using two screen one for list of the record , 

2.make a link for second screen and pass input parameter as identifier of your entity ,

3.Fetch the record from entity using aggregate by the ID.

4. and display the record which you want. 

5. If you are making detail screen and then you can use expression or if using input widget , it have Enable property set as False.

like below image-

 

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Siddhi Amilkanthwar

Hi @Rahul Sahu

Thank you so much. Now I got what to do. 


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Siddhi Amilkanthwar

Hi @Rahul Sahu,

I tried with your approach but I am unable to do it. It would be really helpful if you could provide me with a sample oml file. 

Thank you. 

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