Hi @Priya Naveen 

you Can used this function to Achieve your Requirement.

Replace(Name,Substr(Name,Index(Name,"5",searchFromEnd:True)-1,Index(Name,"5",searchFromEnd:True)),"6")

I have Attached oml file so please go through this:

Thanks

Md Mansur

Sadly this is not available in OutSystems. You need to loop it.

Or you can convert string in to character list and use listfiter and join output again.

Hi @Priya Naveen,

You can use javascript to replace below is the syntax:

let var1 = "a5b5ccc5d"; 

let var2 = var1.replace(/5(?!.*5)/, '6');

$parameters.Out1 = newString;

Hope this helps you!!

Regards,

Rajat

By using client action you can also use JavaScript (regular expression). Check the following example

https://personal-u1aragiz.outsystemscloud.com/Testa/JSRegularExpressionTest?_ts=638592486105082121

Hi @Priya Naveen,

Use this expression. 

Name =M5a5n5s5u5r5885r3

Output : M5a5n5s5u5r5886r3 

Substr(Name,0,Index(Name,"5",searchFromEnd:True))+Replace(Substr(Name,Index(Name,"5",searchFromEnd:True),Length(Name)-1),"5","6")

I also attached OML file.
Hope this will help you.

Kind regards,

Susheel Yadav

Hi Priya,

Susheel has mostly given you an answer that works, though I wouldn't use Replace() if there's only a single character to replace and you know it's position.

Like Susheel showed, you can use the built-in Index() function with searchFromEnd True to find the last occurence of a "5". Once you have that position you can use two Substr() functions to get the part before the returned index, and the part after it, and concatenate that. Something like:

Substr(MyVar, 0, Index) + "6" + Substr(MyVar, Index + 1, 1000)

(where 1000 is some arbitrarily large number).